코딩테스트 풀이/Codility

Codility lesson3 - FrogJmp

Essense 2022. 4. 20. 08:01
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fun solution(X: Int, Y: Int, D: Int): Int {
    if (X==Y) return 0

    return if ((Y-X)%D==0) (Y-X)/D else ((Y-X)/D)+1
}

 

 

https://app.codility.com/demo/results/trainingR5ZNAU-87U/

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